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3d-coordinate-geometry Formula Sheet

This page will help you to revise formulas and concepts of 3d-coordinate-geometry instantly for various exams.
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In three-dimensional space, a line is a straight path that extends infinitely in two opposite directions, defined by a point and a direction vector. Conversely, a plane is a flat surface extending infinitely in all directions, defined by a point and two non-parallel direction vectors or by a point and a normal vector perpendicular to the plane.

Neetesh Kumar | May 08, 2024                                       \space \space \space \space \space \space \space \space \space \space \space \space \space \space \space \space \space \space \space \space \space \space \space \space \space \space \space \space \space \space \space \space \space \space \space \space \space \space Share this Page on: Reddit icon Discord icon Email icon WhatsApp icon Telegram icon

1. Distance Formula in 3-D :

The distance between two points A (x1,y1,z1x_1, y_1, z_1) and B (x2,y2,z2x_2, y_2, z_2) in 3-d is given by AB = (x2x1)2+(y2y1)2+(z2z1)2\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2 + (z_2 - z_1)^2}

2. Section Formula in 3-D:

Let the point C (x, y, z) divide the line segment AB joining points A (x1,y1,z1x_1, y_1, z_1) and B (x2,y2,z2x_2, y_2, z_2) in the ratio of m1:m2m_1: m_2, then Coordinates of Point C can be obtained as:
(x, y, z) = (m1x2+m2x1m1+m2,m1y2+m2y1m1+m2,m1z2+m2z1m1+m2)\bigg(\frac{m_1x_2+m_2x_1}{m_1+m_2}, \frac{m_1y_2+m_2y_1}{m_1+m_2}, \frac{m_1z_2+m_2z_1}{m_1+m_2}\bigg)

  • If m1m2\frac{m_1}{m_2} is Positive\bold{Positive}, it means C divides the line segment AB Internally\bold{Internally}.
  • If m1m2\frac{m_1}{m_2} is Negative\bold{Negative}, it means C divides the line segment AB Externally\bold{Externally}.
  • Mid Point of AB is given by (x2+x12,y2+y12,z2+z12)\bigg(\frac{x_2+x_1}{2}, \frac{y_2+y_1}{2}, \frac{z_2+z_1}{2}\bigg)

3. Centroid of a Triangle in 3-D:

Consider the points A (x1,y1,z1x_1, y_1, z_1), B (x2,y2,z2x_2, y_2, z_2) and C (x3,y3,z3x_3, y_3, z_3) be the vertices of a triangle ABC. Then its centroid G is given by
G = (x1+x2+x33,y1+y2+y33,z1+z2+z33)(\frac{x_1+x_2+x_3}{3}, \frac{y_1+y_2+y_3}{3}, \frac{z_1+z_2+z_3}{3})

4. Direction Cosines of a Line:

If α, β, γ g be the angles made by a line with x-axis, y-axis & z-axis respectively then cosα, cosβ & cosγ are called direction cosines of a line, denoted by l, m & n resp. and the relation between l, m, n is given by l2 + m2 + n2 = 1
Direction Cosines of the x-axis, y-axis, and z-axis are (1, 0, 0), (0, 1, 0), (0, 0, 1)respectively

Direction Cosines of a Line

5. Direction Ratios of a Line:

Three numbers a, b, and c proportional to direction cosines l, m, n are called direction ratios of the line.
i.e. la=mb=nc\frac{l}{a} = \frac{m}{b} = \frac{n}{c} There exist infinitely many sets of direction ratios for a given line.

6. Relation between Direction cosines & Direction Ratios:

We know that la=mb=nc\frac{l}{a} = \frac{m}{b} = \frac{n}{c}
Now, by squaring and adding the above terms
l2a2=m2b2=n2c2=l2+m2+n2a2+b2+c2\therefore \frac{l^2}{a^2} = \frac{m^2}{b^2} = \frac{n^2}{c^2} = \frac{l^2+m^2+n^2}{a^2+b^2+c^2}
\therefore l=±aa2+b2+c2;l = \frac{\plusmn a}{\sqrt{a^2+b^2+c^2}}; m=±ba2+b2+c2;m = \frac{\plusmn b}{\sqrt{a^2+b^2+c^2}}; n=±ca2+b2+c2n = \frac{\plusmn c}{\sqrt{a^2+b^2+c^2}}

7. Direction Ratios & Cosines of a Line joining two Points:

Let P (x1,y1,z1x_1, y_1, z_1) and Q (x2,y2,z2x_2, y_2, z_2) be two points of a line segment, then Direction Ratios of PQ are (x2x1,y2y1,z2z1)(x_2 - x_1, y_2 - y_1, z_2 - z_1) and Direction Cosines are x2x1r,\frac{x_2 - x_1}{r}, y2y1r,\frac{y_2 - y_1}{r}, z2z1r\frac{z_2 - z_1}{r} where r = AB|\overrightarrow{AB}| is the distance between A and B.

8. Projection of a Line on another line:

Let AB be a line segment with A (x1,y1,z1x_1, y_1, z_1) and B (x2,y2,z2x_2, y_2, z_2), and let L be a straight line whose direction cosines are l, m, n. Then the length of the projection of AB on the line L is l(x2x1)+m(y2y1)+n(z2z1)|l(x_2 - x_1) + m(y_2 - y_1) + n(z_2 - z_1)|

9. Angle between two lines in 3-D:

Consider two lines with direction cosines l1,m1,n1l_1, m_1, n_1 and l2,m2,n2l_2, m_2, n_2 and angle between them is θ\theta then cosθ=l1l2+m1m2+n1n2.\theta =l_1l_2 + m_1m_2 + n_1n_2.
If the direction ratios of these lines are a1,b1,c1a_1, b_1, c_1 and a2,b2,c2a_2, b_2, c_2 then Cosθ=a1a2+b1b2+c1c2(a12+b12+c12)(a22+b22+c22)\theta = \frac{a_1a_2 + b_1b_2 + c_1c_2}{\sqrt{(a_1^2+b_1^2+c_1^2)}\sqrt{(a_2^2+b_2^2+c_2^2)}}

10. Condition for Parallel and Perpendicular Lines in 3-D:

(a)\bold{(a)} Consider two lines with direction cosines l1,m1,n1l_1, m_1, n_1 and l2,m2,n2l_2, m_2, n_2.

  • These lines are Perpendicular if θ=90o\theta=90^o i.r. cosθ=0\theta=0 i.e. (l1l2+m1m2+n1n2=0)\bold{(l_1l_2+m_1m_2+n_1n_2=0)}
  • These lines are Parallel if θ=0o\theta=0^o i.e. sinθ=0\theta=0 i.e. l1l2=m1m2=n1n2\bold{\frac{l_1}{l_2}=\frac{m_1}{m_2}=\frac{n_1}{n_2}}

(b)\bold{(b)} Consider two lines with direction ratios a1,b1,c1a_1, b_1, c_1 and a2,b2,c2a_2, b_2, c_2.

  • These lines are Perpendicular if θ=90o\theta=90^o i.r. cosθ=0\theta=0 i.e. (a1a2+b1b2+c1c2=0)\bold{(a_1a_2+b_1b_2+c_1c_2=0)}
  • These lines are Parallel if θ=0o\theta=0^o i.e. sinθ=0\theta=0 i.e. a1a2=b1b2=c1c2\bold{\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}}

11. Equation of Lines in Parametric form:

(a)\bold{(a)} Let the Equation of the line through two points be a given point on the line and l, m, n the direction cosines of the line, then its equation is
xx1l=yy1m=zz1n=t\frac{x-x_1}{l} = \frac{y-y_1}{m} = \frac{z-z_1}{n} = t (let)
From the above equation, the general point on the line is P (x1+tl,x2+tm,x3+tn)(x_1+tl, x_2+tm, x_3+tn) and it is located at a distance of t units from the point A (x1,y1,z1)(x_1, y_1, z_1) i.e. AP = t. This condition only holds for direction cosines but not for direction ratios.
If a, b, and c are the direction ratios of the line, then the equation of the line is
xx1a=yy1b=zz1c=t\frac{x-x_1}{a} = \frac{y-y_1}{b} = \frac{z-z_1}{c} = t (let)
but here AP \ne r

(b)\bold{(b)} Equation of the line through two points A (x1,y1,z1)(x_1, y_1, z_1) and B (x2,y2,z2)(x_2, y_2, z_2) is xx1x2x1=yy1y2y1=zz1z2z1\frac{x-x_1}{x_2-x_1} = \frac{y-y_1}{y_2-y_1} = \frac{z-z_1}{z_2-z_1}

12. Length & Equation of Perpendicular from a point to a Line:

Let equation of the line be xx1l=yy1m=zz1n=r\frac{x-x_1}{l} = \frac{y-y_1}{m} = \frac{z-z_1}{n} = r (let) ....(i)
and A (α,β,γ\alpha, \beta, \gamma) be the point.
Then any general point on the line (i) is P (lr+x1,mr+y1,nr+z1lr + x_1, mr + y_1, nr + z_1) .....(ii)
If it is the foot of the perpendicular, from A on the line, then AP is \perp to the line,
So l(r+x1α)+m(mr+y1β)+n(nr+z1γ)=0l(r + x_1 - \alpha) + m(mr + y_1 - \beta) + n(nr + z_1 - \gamma) = 0 i.e.
r = (αx1)l+(βy1)m+(γz1)n(\alpha - x_1)l + (\beta - y_1)m + (\gamma - z_1)n
Since l2+m2+n2=1l^2 + m^2 + n^2 = 1
Putting this value of r in (ii), we get the foot of the perpendicular from point A to the line.

Length:\bold{Length:} Since the foot of perpendicular P is known, the length of perpendicular is
AP = [(lr+x1α)2+(mr+y1β)2+(nr+z1γ)2]\sqrt{[(lr+x_1-\alpha)^2 + (mr+y_1-\beta)^2 + (nr+z_1-\gamma)^2]}
Equation of Perpendicular: xαlr+x1α=yβmr+y1β=zγnr+z1γ\frac{x-\alpha}{lr+x_1-\alpha} = \frac{y-\beta}{mr+y_1-\beta} = \frac{z-\gamma}{nr+z_1-\gamma}

13. Equation of Planes in various forms:

The equation of every plane is of the first degree, i.e., of the form ax + by + cz + d = 0, in which a, b, and c are constants, where a2+b2+c20a^2+b^2+c^2\ne0 (i.e., a, b, and c 0\ne 0 simultaneously).
(a)\bold{(a)} Vector form of equation of plane :
If a\vec{a} is the position vector of a point on the plane and n\vec{n} is a vector normal to the plane,
then its vectorial equation is given by
(r\vec{r} - a\vec{a}).n=0r.n=d\vec{n} = 0 \Rightarrow \vec{r}.\vec{n}=d where d=a.n=constant.d = \vec{a}.\vec{n}=constant.

(b)\bold{(b)} Planes Parallel to the Coordinate Planes :

  • The equation of the y-z plane is x = 0.
  • The equation of the z-x plane is y = 0.
  • The equation of the x-y plane is z = 0.
  • The equation of the plane parallel to the x-y plane at a distance c is z = c. Similarly, planes parallel to the y-z and z-x planes are x = c and y = c respectively.

(c)\bold{(c)} Equations of Planes Parallel to the Axes :

  • If a = 0, the plane is parallel to the x-axis, i.e., the equation of the plane parallel to the x-axis is by + cz + d = 0.
  • Similarly, equations of planes parallel to the y-axis and parallel to the z-axis are ax + cz + d = 0 and ax + by + d = 0, respectively.

(d)\bold{(d)} Equation of a Plane in Intercept Form :
The equation of the plane which cuts off intercepts a, b, and c from the axes is xa+yb+zc=1\frac{x}{a} + \frac{y}{b} + \frac{z}{c} = 1

(e)\bold{(e)} Equation of a Plane in Normal Form :
If the length of the perpendicular distance of the plane from the origin is p and the direction cosines of this perpendicular are (l, m, n), then the equation of the plane is lx + my + nz = p.

(f)\bold{(f)} Vectorial form of Normal equation of plane :
If n^\hat{n} is a unit vector normal to the plane from the origin to the plane and d be the perpendicular distance of the plane from the origin, then its vector equation is r.n^=d\vec{r}.\hat{n}=d

(g)\bold{(g)} Equation of a Plane through three points :
The equation of the plane through three non-collinear points A(x1,y1,z1x_1, y_1, z_1), B(x2,y2,z2x_2, y_2, z_2), C(x3,y3,z3x_3, y_3, z_3) is xyz1x1y1z11x2y2z21x3y3z31=0\begin{vmatrix} x & y & z & 1 \\ x_1 & y_1 & z_1 & 1 \\ x_2 & y_2 & z_2 & 1 \\ x_3 & y_3 & z_3 & 1 \\ \end{vmatrix} = 0

14. The angle between two Planes:

  • Consider two planes ax + by + cz + d = 0 and a' x + b' y + c' z + d' = 0.
    The angle between these planes is the angle between their normals.
    Cosθ=aa+bb+cca2+b2+c2a2+b2+c2\theta = \frac{aa' + bb' + cc'}{\sqrt{a^2+b^2+c^2}\sqrt{a'^2+b'^2+c'^2}}
  • Planes are perpendicular if aa' + bb' + cc' = 0 and they are parallel
    if aa=bb=cc\frac{a}{a'} = \frac{b}{b'} = \frac{c}{c'}

Planes parallel to a given Plane:
The equation of a plane parallel to the plane ax + by + cz + d = 0
is ax + by + cz + d' = 0. d' is to be found by other given conditions.

15. The angle between a line and Plane :

Let equations of the line be xx1l=yy1m=zz1n\frac{x-x_1}{l} = \frac{y-y_1}{m} = \frac{z-z_1}{n} and plane be ax + by + cz + d = 0 respectively and θ\theta be the angle which line makes with the plane.
Then (π2θ)(\frac{\pi}{2} - \theta) is the angle between the line and the normal to the plane.
Sinθ=al+bm+cna2+b2+c2l2+m2+n2\theta = \frac{al + bm + cn}{\sqrt{a^2+b^2+c^2}\sqrt{l^2+m^2+n^2}}

  • If the Line is parallel to the plane, then θ=0\theta = 0, i.e. if al + bm + cn = 0.
  • Line is \perp to the plane if the line is parallel to the normal of the plane, i.e., if al=bm=cn\frac{a}{l} = \frac{b}{m} = \frac{c}{n}

16. Condition for Line to lie on Plane:

The xx1l=yy1m=zz1n\frac{x-x_1}{l} = \frac{y-y_1}{m} = \frac{z-z_1}{n} will lie on the plane Ax+By+Cz+D=0Ax + By + Cz + D = 0 if

  • Al+Bm+Cn=0Al + Bm + Cn = 0 and
  • Ax1+By1+Cz1+D=0Ax_1 + By_1 + Cz_1 + D = 0

17. Position of two points with respect to a Plane:

Two points P(x1,y1,z1x_1, y_1, z_1) & Q(x2,y2,z2x_2, y_2, z_2) are on the same or opposite sides of a plane ax+by+cz+d=0ax + by + cz + d = 0 according to the sign of ax1+by1+cz1+dax_1+by_1+cz_1+d and ax2+by2+cz2+dax_2+by_2+cz_2+d.

  • If Signs are the same, then Points P & Q lie on the same side of the plane.
  • If Signs are opposite, then Points P & Q lie on the opposite side of the plane.

18. Image of a Point in the Plane:

An image Q(x2,y2,z2x_2, y_2, z_2) of a point P (x1,y1,z1x_1, y_1, z_1) in a plane ax + by + cz + d = 0 is
x2x1a=y2y1b=z2z1c=2(ax1+by1+cz1+da2+b2+c2)\frac{x_2-x_1}{a} = \frac{y_2-y_1}{b} = \frac{z_2-z_1}{c} = -2(\frac{ax_1+by_1+cz_1+d}{a^2+b^2+c^2})
And the coordinates of the foot of perpendicular Q(x3,y3,z3x_3, y_3, z_3) of point P (x1,y1,z1x_1, y_1, z_1) on the plane ax + by + cz + d = 0 is

x3x1a=y3y1b=z3z1c=(ax1+by1+cz1+da2+b2+c2)\frac{x_3-x_1}{a} = \frac{y_3-y_1}{b} = \frac{z_3-z_1}{c} = -(\frac{ax_1+by_1+cz_1+d}{a^2+b^2+c^2})

19. Condition for the Lines to be Coplanar:

Let the equation of the lines be
xα1l1=yβ1m1=zγ1n1\frac{x-\alpha_1}{l_1} = \frac{y-\beta_1}{m_1} = \frac{z-\gamma_1}{n_1} .....(i) and
xα2l2=yβ2m2=zγ2n2\frac{x-\alpha_2}{l_2} = \frac{y-\beta_2}{m_2} = \frac{z-\gamma_2}{n_2} .....(ii)

These lines are coplanar if α2α1β2β1γ2γ1l1m1n1l2m2n2=0\begin{vmatrix} \alpha_2-\alpha_1 & \beta_2-\beta_1 & \gamma_2 - \gamma_1 \\ l_1 & m_1 & n_1 \\ l_2 & m_2 & n_2 \\ \end{vmatrix} = 0
the plane containing the two lines is xα1yβ1zγ1l1m1n1l2m2n2=0\begin{vmatrix} x-\alpha_1 & y-\beta_1 & z - \gamma_1 \\ l_1 & m_1 & n_1 \\ l_2 & m_2 & n_2 \\ \end{vmatrix} = 0

20. Distance of a Point from the Plane:

Perpendicular distance p, of the point P(x1,y1,z1x_1, y_1, z_1) from the plane ax + by + cz + d = 0 is given by
P = ax1+by1+cz1+d(a2+b2+c2)\frac{|ax_1+by_1+cz_1+d|}{\sqrt{(a^2+b^2+c^2)}}
Distance d between two parallel planes ax+by+cz+d1=0ax + by + cz + d_1 = 0 and ax+by+cz+d2=0ax + by + cz + d_2 = 0 is
d = d2d1a2+b2+c2|\frac{d_2 - d_1}{\sqrt{a^2+b^2+c^2}}|

21. Equation of a Plane through the line of intersection of two planes:

Consider two planes u=ax+by+cz+d=0u = ax + by + cz + d = 0 and v=ax+by+cz+d=0.v = a'x + b'y + c'z + d' = 0.
The equation u+λv=0,u + \lambda v = 0, where λ\lambda a real parameter, represents the plane passing through the line of intersection of given planes, and if planes are parallel, this represents a plane parallel to them

22. Angle bisectors between two planes:

Let the equations of the two planes be ax+by+cz+d=0ax + by + cz + d = 0 and px+qy+rz+s=0.px + qy + rz + s = 0.
Then equations of bisectors of angles between them are given by

ax+by+cz+da2+b2+c2=±(px+qy+rz+sp2+q2+r2)\frac{ax + by + cz + d}{\sqrt{a^2 + b^2 + c^2}} = \plusmn (\frac{px + qy + rz + s}{\sqrt{p^2 + q^2 + r^2}})

  • Equation of bisector of the angle containing origin:
    First, make both constant terms positive.
    Then, the +ve sign gives the bisector of the angle that contains the origin.

  • Bisector of acute/obtuse angle:
    First, making both constant terms positive,
    ap+bq+cr>0ap + bq + cr > 0 \Rightarrow origin lies in obtuse angle
    ap+bq+cr<0ap + bq + cr < 0 \Rightarrow origin lies in acute angle

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