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What is the value of f(0)f(0) for the function f(x)=log1010+9x+(x2)(x1)f(x) = \log_{10} 10 + 9^x + (x - 2)(x - 1)?

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Question :

What is the value of f(0)f(0) for the function f(x)=log1010+9x+(x2)(x1)f(x) = \log_{10} 10 + 9^x + (x - 2)(x - 1)?

What is the value of f(0) for the function $$ f(x) = \log_{10} 10 + 9^x + (x - | Doubtlet.com

Solution:

Neetesh Kumar

Neetesh Kumar | October 23, 2024

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CLEPS College Algebra Guide Question 74
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Step-by-step solution:

We need to find ( f(0) ), which means substituting ( x = 0 ) into the function.

Step 1: Evaluate ( \log_{10} 10 )

We know that:

log1010=1\log_{10} 10 = 1

So, the first term is 1.

Step 2: Evaluate ( 9^x ) at ( x = 0 )

When ( x = 0 ), we have:

90=19^0 = 1

Step 3: Evaluate ( (x - 2)(x - 1) ) at ( x = 0 )

Substitute ( x = 0 ) into the expression ( (x - 2)(x - 1) ):

(02)(01)=(2)(1)=2(0 - 2)(0 - 1) = (-2)(-1) = 2

Step 4: Add the terms together

Now, add all the evaluated terms:

f(0)=1+1+2=4f(0) = 1 + 1 + 2 = 4


Final Answer:

The value of ( f(0) ) is: 4\boxed{4}



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