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(a) Find at least 1010 partial sums of the series. (Round your answers to five decimal places.) n=19(2)n.\displaystyle\sum_{n=1}^\infty \frac{9}{(-2)^n}.

nnsns_n
1?\boxed{?}
2?\boxed{?}
3?\boxed{?}
4?\boxed{?}
5?\boxed{?}
6?\boxed{?}
7?\boxed{?}
8?\boxed{?}
9?\boxed{?}
10?\boxed{?}

(b) Graph both the sequence of terms and the sequence of partial sums on the same screen. Does it appear that the series is convergent or divergent? If it is convergent, find the sum. (If the quantity diverges, enter DIVERGES.)

?\boxed{?}

(c) If it is divergent, explain why.

  • The terms of the series do not approach 00.
  • The sequence of partial sums is divergent.
  • The series is convergent.

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Question :

(a) find at least 1010 partial sums of the series. (round your answers to five decimal places.) n=19(2)n.\displaystyle\sum_{n=1}^\infty \frac{9}{(-2)^n}.

nnsns_n
1?\boxed{?}
2?\boxed{?}
3?\boxed{?}
4?\boxed{?}
5?\boxed{?}
6?\boxed{?}
7?\boxed{?}
8?\boxed{?}
9?\boxed{?}
10?\boxed{?}

(b) graph both the sequence of terms and the sequence of partial sums on the same screen. does it appear that the series is convergent or divergent? if it is convergent, find the sum. (if the quantity diverges, enter diverges.)

?\boxed{?}

(c) if it is divergent, explain why.

  • the terms of the series do not approach 00.
  • the sequence of partial sums is divergent.
  • the series is convergent.

(a) find at least 10 partial sums of the series. (round your answers to fi | Doubtlet.com

Solution:

Neetesh Kumar

Neetesh Kumar | December 27, 2024

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This is the solution to Math 1c
Assignment: 11.2 Question Number 3
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Step-by-step solution:

Step 1: Write the series and general term:

The series is:

n=19(2)n.\displaystyle\sum_{n=1}^\infty \frac{9}{(-2)^n}.

The nn-th term of the series is given by:

an=9(2)n.a_n = \frac{9}{(-2)^n}.

Step 2: Compute partial sums:

The partial sum sns_n is the sum of the first nn terms:

sn=k=1nak.s_n = \displaystyle\sum_{k=1}^n a_k.

We calculate sns_n for n=1,2,,10n = 1, 2, \dots, 10:

  1. s1=9(2)1=4.5s_1 = \frac{9}{(-2)^1} = -4.5
  2. s2=9(2)1+9(2)2=4.5+2.25=2.25s_2 = \frac{9}{(-2)^1} + \frac{9}{(-2)^2} = -4.5 + 2.25 = -2.25
  3. s3=4.5+2.25+9(2)3=4.5+2.251.125=3.375s_3 = -4.5 + 2.25 + \frac{9}{(-2)^3} = -4.5 + 2.25 - 1.125 = -3.375
  4. s4=3.375+9(2)4=3.375+0.5625=2.8125s_4 = -3.375 + \frac{9}{(-2)^4} = -3.375 + 0.5625 = -2.8125
  5. s5=2.8125+9(2)5=2.81250.28125=3.09375s_5 = -2.8125 + \frac{9}{(-2)^5} = -2.8125 - 0.28125 = -3.09375
  6. s6=3.09375+9(2)6=3.09375+0.140625=2.95313s_6 = -3.09375 + \frac{9}{(-2)^6} = -3.09375 + 0.140625 = -2.95313
  7. s7=2.95312+9(2)7=2.953130.07031=3.02344s_7 = -2.95312 + \frac{9}{(-2)^7} = -2.95313 - 0.07031 = -3.02344
  8. s8=3.02344+9(2)8=3.02344+0.035157=2.988281s_8 = -3.02344 + \frac{9}{(-2)^8} = -3.02344 + 0.035157 = -2.988281
  9. s9=2.98828+9(2)9=2.9882810.01758=3.00586s_9 = -2.98828 + \frac{9}{(-2)^9} = -2.988281 - 0.01758 = -3.00586
  10. s10=3.00586+9(2)10=3.00586+0.00879=2.99701s_{10} = -3.00586 + \frac{9}{(-2)^{10}} = -3.00586 + 0.00879 = -2.99701
nnsns_n
14.5-4.5
22.25-2.25
33.375-3.375
42.8125-2.8125
53.09375-3.09375
62.95313-2.95313
73.0234-3.0234
82.98821-2.98821
93.00586-3.00586
102.99701-2.99701

Step 3: Graph the sequences:

Plot the sequence of terms ana_n and the sequence of partial sums sns_n.

Step 4: Analyze convergence:

To determine convergence, we observe the behavior of sns_n as nn \to \infty.

  • The sequence of partial sums sns_n approaches a limit near 3-3. Therefore, the series appears to be convergent.
  • The sum of the series is approximately:

s=limnsn3.s = \displaystyle\lim_{n \to \infty} s_n \approx -3.

Step 5: Explanation for divergence (if applicable):

If the series were divergent, it would fail to meet one of the following conditions:

  • The terms ana_n would not approach 00.
  • The sequence of partial sums sns_n would not settle to a finite value.

In this case, however, the series converges.

Final Answer:

(a)

nnsns_n
14.5\boxed{-4.5}
22.25\boxed{-2.25}
33.375\boxed{-3.375}
42.8125\boxed{-2.8125}
53.09375\boxed{-3.09375}
62.95313\boxed{-2.95313}
73.0234\boxed{-3.0234}
82.98821\boxed{-2.98821}
93.00586\boxed{-3.00586}
102.99701\boxed{-2.99701}

(b) 3\boxed{-3}

(c) the series convergent\boxed{\text{the series convergent}}


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