Neetesh Kumar | December 27, 2024
Calculus Homework Help
This is the solution to Math 1c
Assignment: 11.2 Question Number 3
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Step-by-step solution:
Step 1: Write the series and general term:
The series is:
n=1∑∞(−2)n9.
The n-th term of the series is given by:
an=(−2)n9.
Step 2: Compute partial sums:
The partial sum sn is the sum of the first n terms:
sn=k=1∑nak.
We calculate sn for n=1,2,…,10:
- s1=(−2)19=−4.5
- s2=(−2)19+(−2)29=−4.5+2.25=−2.25
- s3=−4.5+2.25+(−2)39=−4.5+2.25−1.125=−3.375
- s4=−3.375+(−2)49=−3.375+0.5625=−2.8125
- s5=−2.8125+(−2)59=−2.8125−0.28125=−3.09375
- s6=−3.09375+(−2)69=−3.09375+0.140625=−2.95313
- s7=−2.95312+(−2)79=−2.95313−0.07031=−3.02344
- s8=−3.02344+(−2)89=−3.02344+0.035157=−2.988281
- s9=−2.98828+(−2)99=−2.988281−0.01758=−3.00586
- s10=−3.00586+(−2)109=−3.00586+0.00879=−2.99701
n | sn |
---|
1 | −4.5 |
2 | −2.25 |
3 | −3.375 |
4 | −2.8125 |
5 | −3.09375 |
6 | −2.95313 |
7 | −3.0234 |
8 | −2.98821 |
9 | −3.00586 |
10 | −2.99701 |
Step 3: Graph the sequences:
Plot the sequence of terms an and the sequence of partial sums sn.
Step 4: Analyze convergence:
To determine convergence, we observe the behavior of sn as n→∞.
- The sequence of partial sums sn approaches a limit near −3. Therefore, the series appears to be convergent.
- The sum of the series is approximately:
s=n→∞limsn≈−3.
Step 5: Explanation for divergence (if applicable):
If the series were divergent, it would fail to meet one of the following conditions:
- The terms an would not approach 0.
- The sequence of partial sums sn would not settle to a finite value.
In this case, however, the series converges.
Final Answer:
(a)
n | sn |
---|
1 | −4.5 |
2 | −2.25 |
3 | −3.375 |
4 | −2.8125 |
5 | −3.09375 |
6 | −2.95313 |
7 | −3.0234 |
8 | −2.98821 |
9 | −3.00586 |
10 | −2.99701 |
(b) −3
(c)
the series convergent
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