Neetesh Kumar | December 27, 2024
Calculus Homework Help
This is the solution to Math 1c
Assignment: 11.2 Question Number 4
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Step-by-step solution:
Step 1: Analyze the series:
The series involves the general term:
an=cos(9n).
The partial sum Sn is defined as:
Sn=k=1∑ncos(9k).
To evaluate the behavior of Sn, we need to compute the first 10 partial sums.
Step 2: Compute the first 10 partial sums:
Using a calculator or computational tool, evaluate:
-
For n=1:
S1=cos(9⋅1)=cos(9)≈−0.911130.
-
For n=2:
S2=S1+cos(9⋅2)=−0.911130+cos(18)≈−0.91113+0.6603167=−0.250813.
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For n=3:
S3=S2+cos(9⋅3)=−0.250813+cos(27)≈−0.250813−0.29213880=−0.5429518.
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For n=4:
S4=S3+cos(9⋅4)=−0.5429518+cos(36)≈−0.5429518−0.12796=−0.67091.
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For n=5:
S5=S4+cos(9⋅5)=−0.67091+cos(45)≈−0.67091+0.52532=−0.14559.
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For n=6:
S6=S5+cos(9⋅6)=−0.14559+cos(54)≈−0.14559−0.82930=−0.9749.
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For n=7:
S7=S6+cos(9⋅7)=−0.9749+cos(63)≈−0.9749+0.98589=0.01099.
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For n=8:
S8=S7+cos(9⋅8)=0.01099+cos(72)≈0.01099−0.967250=−0.95625.
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For n=9:
S9=S8+cos(9⋅9)=−0.95625+cos(81)≈−0.95625+0.776685=−0.17957.
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For n=10:
S10=S9+cos(9⋅10)=−0.17957+cos(90)≈−0.17957−0.44807=−0.62764.
Step 3: Populate the table:
n | Sn |
---|
1 | −0.911130 |
2 | −0.250813 |
3 | −0.542952 |
4 | −0.67091 |
5 | −0.14559 |
6 | −0.9749 |
7 | 0.01099 |
8 | −0.95625 |
9 | −0.17957 |
10 | −0.62764 |
Step 4: Convergence or divergence:
The partial sums Sn do not settle to a fixed value as n increases. Instead, the values oscillate due to the periodic nature of the cosine function. Therefore, the series diverges.
Final Answer:
(a)
n | sn |
---|
1 | −0.911130 |
2 | −0.250813 |
3 | −0.542952 |
4 | −0.67091 |
5 | −0.14559 |
6 | −0.9749 |
7 | 0.01099 |
8 | −0.95625 |
9 | −0.17957 |
10 | −0.62764 |
(b)
- The series diverges
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