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Consider the following: x=5cos(θ),y=6sin(θ),π2θπ2x = 5 \cos(\theta), \quad y = 6 \sin(\theta), \quad -\frac{\pi}{2} \leq \theta \leq \frac{\pi}{2}

(a) Eliminate the parameter to find a Cartesian equation of the curve.

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Question :

Consider the following: x=5cos(θ),y=6sin(θ),π2θπ2x = 5 \cos(\theta), \quad y = 6 \sin(\theta), \quad -\frac{\pi}{2} \leq \theta \leq \frac{\pi}{2}

(a) eliminate the parameter to find a cartesian equation of the curve.

Consider the following:
$x = 5 \cos(\theta), \quad y = 6 \sin(\theta), \quad -\ | Doubtlet.com

Solution:

Neetesh Kumar

Neetesh Kumar | January 3, 2025

Calculus Homework Help

This is the solution to Math 1c
Assignment: 10.1 Question Number 13
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Step-by-step solution:

Step 1: Express cos(θ)\cos(\theta) and sin(θ)\sin(\theta) in terms of xx and yy

From the first equation:

x=5cos(θ)x = 5 \cos(\theta), so cos(θ)=x5\cos(\theta) = \frac{x}{5}.

From the second equation:

y=6sin(θ)y = 6 \sin(\theta), so sin(θ)=y6\sin(\theta) = \frac{y}{6}.

Step 2: Use the Pythagorean identity

The Pythagorean identity is:

cos2(θ)+sin2(θ)=1\cos^2(\theta) + \sin^2(\theta) = 1.

Substitute cos(θ)=x5\cos(\theta) = \frac{x}{5} and sin(θ)=y6\sin(\theta) = \frac{y}{6} into the identity:

(x5)2+(y6)2=1\left(\frac{x}{5}\right)^2 + \left(\frac{y}{6}\right)^2 = 1.

Step 3: Simplify the equation

x225+y236=1\frac{x^2}{25} + \frac{y^2}{36} = 1.

Final Cartesian Equation

The Cartesian equation of the curve is:

x225+y236=1\boxed{\frac{x^2}{25} + \frac{y^2}{36} = 1}


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