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Find a Cartesian equation for the curve: r=5cos(θ)r = 5\cos(\theta)

?\boxed{?}

Identify the curve from the following options:

  • Circle
  • Limaçon
  • Line
  • Ellipse
  • Hyperbola

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Question :

Find a cartesian equation for the curve: r=5cos(θ)r = 5\cos(\theta)

?\boxed{?}

identify the curve from the following options:

  • circle
  • limaçon
  • line
  • ellipse
  • hyperbola

![Find a cartesian equation for the curve: r=5cos(θ)r = 5\cos(\theta)

?\boxed{?} | Doubtlet.com](https://doubt.doubtlet.com/images/20250102-192111-10.3.4.png)

Solution:

Neetesh Kumar

Neetesh Kumar | January 2, 2025

Calculus Homework Help

This is the solution to Math 1c
Assignment: 10.3 Question Number 4
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Step-by-step solution:

Step 1: Convert the polar equation to Cartesian form:

The relationships between polar and Cartesian coordinates are:

  1. x=rcos(θ)x = r\cos(\theta)
  2. y=rsin(θ)y = r\sin(\theta)
  3. r2=x2+y2r^2 = x^2 + y^2

The given equation is r=5cos(θ)r = 5\cos(\theta).

Multiply both sides by rr to eliminate rr from the denominator:

r2=5rcos(θ)r^2 = 5r\cos(\theta)

Using r2=x2+y2r^2 = x^2 + y^2 and rcos(θ)=xr\cos(\theta) = x, substitute these into the equation:

x2+y2=5xx^2 + y^2 = 5x

Step 2: Simplify the equation:

Rearrange the terms:

x2+y25x=0x^2 + y^2 - 5x = 0

Complete the square for the xx terms. Add and subtract (52)2=254\left(\frac{5}{2}\right)^2 = \frac{25}{4}:

x25x+254+y2=254x^2 - 5x + \frac{25}{4} + y^2 = \frac{25}{4}

Simplify:

(x52)2+y2=254\left(x - \frac{5}{2}\right)^2 + y^2 = \frac{25}{4}

Step 3: Identify the curve:

The equation (x52)2+y2=254\left(x - \frac{5}{2}\right)^2 + y^2 = \frac{25}{4} represents a circle with:

  • Center at (52,0)\left(\frac{5}{2}, 0\right)
  • Radius 52\frac{5}{2}

Thus, the curve is a circle.

Final Answer:

The Cartesian equation of the curve is:

x2+y25x=0\boxed{x^2 + y^2 - 5x = 0}

The curve is a circle\boxed{\text{circle}}


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