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Find a Cartesian equation for the curve: r=9tan(θ)sec(θ)r = 9 \tan(\theta) \sec(\theta)

?\boxed{?}

Identify the curve from the following options:

  • Parabola
  • Ellipse
  • Limaçon
  • Line
  • Circle

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Question :

Find a cartesian equation for the curve: r=9tan(θ)sec(θ)r = 9 \tan(\theta) \sec(\theta)

?\boxed{?}

identify the curve from the following options:

  • parabola
  • ellipse
  • limaçon
  • line
  • circle

Find a cartesian equation for the curve:
r = 9 \tan(\theta) \sec(\theta)| Doubtlet.com

Solution:

Neetesh Kumar

Neetesh Kumar | January 2, 2025

Calculus Homework Help

This is the solution to Math 1c
Assignment: 10.3 Question Number 6
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Step-by-step solution:

Step 1: Express rr in terms of Cartesian coordinates:

The relationships between polar and Cartesian coordinates are:

  1. x=rcos(θ)x = r\cos(\theta)
  2. y=rsin(θ)y = r\sin(\theta)
  3. tan(θ)=yx\tan(\theta) = \frac{y}{x}
  4. sec(θ)=1cos(θ)\sec(\theta) = \frac{1}{\cos(\theta)}

Given:

r=9tan(θ)sec(θ)r = 9 \tan(\theta) \sec(\theta)

Substitute tan(θ)=yx\tan(\theta) = \frac{y}{x} and sec(θ)=1cos(θ)\sec(\theta) = \frac{1}{\cos(\theta)}:

r=9yx1cos(θ)r = 9 \cdot \frac{y}{x} \cdot \frac{1}{\cos(\theta)}

Now multiply both sides by rcos(θ)r\cos(\theta) to eliminate rr and cos(θ)\cos(\theta):

rcos(θ)=9yxr \cos(\theta) = 9 \frac{y}{x}

From rcos(θ)=xr \cos(\theta) = x, substitute xx:

x=9yxx = 9 \frac{y}{x}

Step 2: Simplify the equation:

Multiply through by xx to get rid of the denominator:

x2=9yx^2 = 9y

Step 3: Identify the curve:

The equation x2=9yx^2 = 9y represents a parabola.

Final Answer:

The Cartesian equation of the curve is:

x2=9y\boxed{x^2 = 9y}

The curve is a parabola\boxed{\text{parabola}}


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