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Find a vector a\mathbf{a} with representation given by the directed line segment AB\overrightarrow{AB}: A(0,2,5),B(4,2,4)A(0, 2, 5), \quad B(4, 2, -4).

Draw AB\overrightarrow{AB} and the equivalent representation a\mathbf{a} starting at the origin.

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Question :

Find a vector a\mathbf{a} with representation given by the directed line segment ab\overrightarrow{ab}: a(0,2,5),b(4,2,4)a(0, 2, 5), \quad b(4, 2, -4).

draw ab\overrightarrow{ab} and the equivalent representation a\mathbf{a} starting at the origin.

Find a vector \mathbf{a} with representation given by the directed line se | Doubtlet.com

Solution:

Neetesh Kumar

Neetesh Kumar | December 18, 2024

Calculus Homework Help

This is the solution to Math 1C
Assignment: 12.2 Question Number 3
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Step-by-step solution:

Step 1: Compute the vector AB\overrightarrow{AB}:

The vector AB\overrightarrow{AB} is calculated using the formula:
AB=x2x1,y2y1,z2z1,\overrightarrow{AB} = \langle x_2 - x_1, y_2 - y_1, z_2 - z_1 \rangle, where A(x1,y1,z1)A(x_1, y_1, z_1) and B(x2,y2,z2)B(x_2, y_2, z_2).

Given:

  • A(0,2,5)A(0, 2, 5),
  • B(4,2,4)B(4, 2, -4).

Substitute the coordinates into the formula:
AB=(40,22,45).\overrightarrow{AB} = (4 - 0, 2 - 2, -4 - 5).

Simplify each component:
AB=(4,0,9).\overrightarrow{AB} = (4, 0, -9).

Step 2: Represent the vector starting at the origin:

The vector a\mathbf{a} starting at the origin (0,0,0)(0, 0, 0) and ending at the same direction as AB\overrightarrow{AB} is:
a=(4,0,9).\mathbf{a} = (4, 0, -9).

  1. The vector AB\overrightarrow{AB} starts at:
    (0,2,5)(0, 2, 5) and ends at (4,2,4)(4, 2, -4).

  2. The vector a\mathbf{a} starts at (0,0,0)(0, 0, 0) and ends at:
    (4,0,9)(4, 0, -9).

Final Answer:

  1. Vector AB\overrightarrow{AB}:
    AB=(4,0,9)\overrightarrow{AB} = \boxed{(4, 0, -9)}

  2. The vector AB\overrightarrow{AB} starts at:
    (0,2,5)\boxed{(0, 2, 5)} and ends at (4,2,4)\boxed{(4, 2, -4)}

  3. The vector a\mathbf{a} starts at (0,0,0)(0, 0, 0) and ends at:
    (4,0,9)\boxed{(4, 0, -9)}


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