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Identify the surface with the given vector equation. r(s,t)=ssin(7t),s2,scos(7t)\mathbf{r}(s, t) = \langle s \sin(7t), s^2, s \cos(7t) \rangle

  • elliptic cylinder
  • circular cylinder
  • plane
  • hyperbolic paraboloid
  • circular paraboloid

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Question :

Identify the surface with the given vector equation. r(s,t)=ssin(7t),s2,scos(7t)\mathbf{r}(s, t) = \langle s \sin(7t), s^2, s \cos(7t) \rangle

  • elliptic cylinder
  • circular cylinder
  • plane
  • hyperbolic paraboloid
  • circular paraboloid

Identify the surface with the given vector equation. $\mathbf{r}(s, t) = \langle | Doubtlet.com

Solution:

Neetesh Kumar

Neetesh Kumar | November 14, 2024

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This is the solution to Math 1D
Assignment: 16.6 Question Number 6
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Step-by-step solution:

To determine the surface type, let’s analyze each component of the given vector equation: r(s,t)=ssin(7t),s2,scos(7t)\mathbf{r}(s, t) = \langle s \sin(7t), s^2, s \cos(7t) \rangle

This vector equation gives the following coordinates:

  • For the x-coordinate: x=ssin(7t)x = s \sin(7t)
  • For the y-coordinate: y=s2y = s^2
  • For the z-coordinate: z=scos(7t)z = s \cos(7t)

Step 1: Analyze the Relationship Between xx, yy, and zz

Notice that both xx and zz contain ss multiplied by trigonometric functions of tt. To find a relationship between xx, yy, and zz, let’s square the xx and zz components and add them: x2=s2sin2(7t)x^2 = s^2 \sin^2(7t) z2=s2cos2(7t)z^2 = s^2 \cos^2(7t)

Adding these two equations: x2+z2=s2(sin2(7t)+cos2(7t))x^2 + z^2 = s^2 (\sin^2(7t) + \cos^2(7t))

Using the identity sin2(7t)+cos2(7t)=1\sin^2(7t) + \cos^2(7t) = 1, we get: x2+z2=s2x^2 + z^2 = s^2

Since y=s2y = s^2, we can substitute yy for s2s^2: x2+z2=yx^2 + z^2 = y

Step 2: Identify the Surface Type

The equation x2+z2=yx^2 + z^2 = y represents a circular paraboloid. This is the standard form of a circular paraboloid, opening along the yy-axis.

Answer:

The correct option is E: circular paraboloid



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