Neetesh Kumar | December 23, 2024
Calculus Homework Help
This is the solution to Math 1c
Assignment: 11.7 Question Number 1
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Step-by-step solution:
Step 1: Analyze the general term of the series:
The general term of the series is:
an=n6+1n5−1.
As n becomes large, the highest powers of n dominate both the numerator and denominator.
To determine the behavior of the series, simplify an for large n:
an∼n6n5=n1.
This suggests that an behaves like the harmonic series term n1, which is divergent.
Step 2: Apply the Limit Comparison Test:
We compare an with the harmonic series n1, which diverges.
The Limit Comparison Test states that if:
n→∞limbnan=L,
where 0<L<∞, then both series either converge or diverge together.
Let bn=n1. Compute the limit:
n→∞limn1n6+1n5−1=n→∞limn6+1n5−1⋅n.
Simplify:
n→∞limn6+1n6−n.
Divide numerator and denominator by n6:
n→∞lim1+n611−n51=1+01−0=1.
Since the limit is L=1, and L is finite and positive, the Limit Comparison Test applies.
Step 3: Conclusion:
Since the harmonic series ∑n1 diverges, and the given series behaves similarly for large n, the series:
n=1∑∞n6+1n5−1
is divergent.
Final Answer:
The series is:
divergent
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