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Use traces to sketch the surface. (If an answer does not exist, enter DNE. Select Update Graph to see your response plotted on the screen. Select the Submit button to grade your response.) x=y2+6z2x = y^2 + 6z^2

Find:

  • (i) (Write an equation for the cross section at z=0z = 0 using xx and yy.)

  • (ii) (Write an equation for the cross section at y=0y = 0 using xx and zz.)

  • (iii) (Write an equation for the cross section at x=6x = -6 using yy and zz.)

  • (iv) (Write an equation for the cross section at x=0x = 0 using yy and zz).

  • (v) (Write an equation for the cross section at x=6x = 6 using yy and zz).

Identify the surface

  • hyperbolic paraboloid
  • elliptic cone
  • hyperboloid of two sheets
  • parabolic cylinder
  • ellipsoid
  • hyperboloid of one sheet
  • elliptic paraboloid
  • elliptic cylinder

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Question :

Use traces to sketch the surface. (if an answer does not exist, enter dne. select update graph to see your response plotted on the screen. select the submit button to grade your response.) x=y2+6z2x = y^2 + 6z^2

find:

  • (i) (write an equation for the cross section at z=0z = 0 using xx and yy.)

  • (ii) (write an equation for the cross section at y=0y = 0 using xx and zz.)

  • (iii) (write an equation for the cross section at x=6x = -6 using yy and zz.)

  • (iv) (write an equation for the cross section at x=0x = 0 using yy and zz).

  • (v) (write an equation for the cross section at x=6x = 6 using yy and zz).

identify the surface

  • hyperbolic paraboloid
  • elliptic cone
  • hyperboloid of two sheets
  • parabolic cylinder
  • ellipsoid
  • hyperboloid of one sheet
  • elliptic paraboloid
  • elliptic cylinder

Use traces to sketch the surface. (if an answer does not exist, enter dne. selec | Doubtlet.com

Solution:

Neetesh Kumar

Neetesh Kumar | December 15, 2024

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This is the solution to Math 1C
Assignment: 12.6 Question Number 8
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Step-by-step solution:

Step 1: Analyze the given equation

The equation of the surface is: x=y2+6z2.x = y^2 + 6z^2.

This represents an elliptic paraboloid since it is quadratic in both yy and zz and linear in xx.

Step 2: Find the cross sections

(i) Cross section at z=0z = 0

Substitute z=0z = 0 into the equation x=y2+6z2x = y^2 + 6z^2:

Answer:

x=y2\boxed{x = y^2}

This is a parabola opening along the xx-axis in the xyxy-plane.

(ii) Cross section at y=0y = 0

Substitute y=0y = 0 into the equation x=y2+6z2x = y^2 + 6z^2:

Answer:

x=6z2\boxed{x = 6z^2}

This is a parabola opening along the xx-axis in the xzxz-plane.

(iii) Cross section at x=6x = -6

Substitute x=6x = -6 into the equation x=y2+6z2x = y^2 + 6z^2: 6=y2+6z2.-6 = y^2 + 6z^2.

Rearrange: y2+6z2=6.y^2 + 6z^2 = -6.

This equation has no real solutions since the left-hand side is always non-negative while the right-hand side is negative. Therefore, the cross section does not exist:

Answer:

DNE\boxed{\text{DNE}}

(iv) Cross section at x=0x = 0

Substitute x=0x = 0 into the equation x=y2+6z2x = y^2 + 6z^2: 0=y2+6z2.0 = y^2 + 6z^2.

Rearrange: y2+6z2=0.y^2 + 6z^2 = 0.

Answer:

y2+6z2=0\boxed{y^2 + 6z^2 = 0}

The only solution is y=0y = 0 and z=0z = 0, so this is a single point at the origin.

(v) Cross section at x=6x = 6

Substitute x=6x = 6 into the equation x=y2+6z2x = y^2 + 6z^2: 6=y2+6z2.6 = y^2 + 6z^2.

Rearrange: y2+6z2=6.y^2 + 6z^2 = 6.

Answer:

y2+6z2=6\boxed{y^2 + 6z^2 = 6}

This represents an ellipse in the yzyz-plane.

Step 3: Identify the surface

The surface x=y2+6z2x = y^2 + 6z^2 is an elliptic paraboloid.

Answer:

elliptic paraboloid\boxed{\text{elliptic paraboloid}}

Final Answer:

(i) Cross section at z=0z = 0

x=y2\boxed{x = y^2}

(ii) Cross section at y=0y = 0

x=6z2\boxed{x = 6z^2}

(iii) Cross section at x=6x = -6

DNE\boxed{\text{DNE}}

(iv) Cross section at x=0x = 0

y2+6z2=0\boxed{y^2 + 6z^2 = 0}

(v) Cross section at x=6x = 6

y2+6z2=6\boxed{y^2 + 6z^2 = 6}

Identify the surface

elliptic paraboloid\boxed{\text{elliptic paraboloid}}


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