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Write the sum as a product: sin(24.4p)+sin(8.4p)\sin(24.4p) + \sin(8.4p)

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Question :

Write the sum as a product: sin(24.4p)+sin(8.4p)\sin(24.4p) + \sin(8.4p)

![Write the sum as a product: sin(24.4p)+sin(8.4p)\sin(24.4p) + \sin(8.4p)

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Solution:

Neetesh Kumar

Neetesh Kumar | October 16, 2024

Pre-Calculus Homework Help

Sum-to-Product and Product-to-Sum Formulas Assignment 9.4 Question 13
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Step-by-step solution:

We will use the sum-to-product identity for sines:

sin(A)+sin(B)=2sin(A+B2)cos(AB2)\sin(A) + \sin(B) = 2 \sin\left(\frac{A+B}{2}\right) \cos\left(\frac{A-B}{2}\right)

For A=24.4pA = 24.4p and B=8.4pB = 8.4p:

  1. Calculate A+B2\frac{A + B}{2}:

    24.4p+8.4p2=16.4p\frac{24.4p + 8.4p}{2} = 16.4p

  2. Calculate AB2\frac{A - B}{2}:

    24.4p8.4p2=8p\frac{24.4p - 8.4p}{2} = 8p

Now apply the identity:

sin(24.4p)+sin(8.4p)=2sin(16.4p)cos(8p)\sin(24.4p) + \sin(8.4p) = 2 \sin(16.4p) \cos(8p)


Final answer:

2sin(16.4p)cos(8p)\boxed{2 \sin(16.4p) \cos(8p)}



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